Tp5

# Gear Configuration 12

Cannot fetch Flickr photo (id: 4961758541). The photo either does not exist, or is private

Here,

f = 2
a = 1
l = 6

from which, we get

(1)
\begin{align} \frac {\omega_{6/1}}{\omega_{2/1}}& =\frac {\omega_6-\omega_1}{\omega_2-\omega_1}\\ \end{align}
(2)
\begin{split} \frac {\omega_{6/1}}{\omega_{2/1}}& =\left(\frac {-N_2}{N_3}\right)\left(\frac {-N_3}{N_4}\right)\left(\frac {N_4}{N_5}\right)\left(\frac {-N_5}{N_6}\right)\\ & =\left(\frac {-N_2N_5}{N_4N_6}\right)\\ \end{split}

Therefore,

(3)
\begin{align} \frac {\omega_6-\omega_1}{\omega_2-\omega_1}&=\left(\frac {-N_2N_5}{N_4N_6}\right)\\ \end{align}

from (1) and the expression above, we get

(4)
\begin{align} \omega_6 & =\left(\frac {-N_2N_5}{N_4N_6}\right)\left(\omega_2 - \omega_1\right) + \omega_1\\ \end{align}

This is the angular velocity of the Ring gear in terms of the angular velocity of the Arm and the angular velocity of the Sun gear for the configuration shown.

page revision: 6, last edited: 08 Sep 2010 19:20